(3x-2)(x-2)=0

Solution for (3x-2)(x-2)=0 equation:

(3x-2)(x-2)=0

We multiply parentheses ..

(+3x^2-6x-2x+4)=0

We get rid of parentheses

3x^2-6x-2x+4=0

We add all the numbers together, and all the variables

3x^2-8x+4=0

a = 3; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·3·4
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*3}=\frac{4}{6}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*3}=\frac{12}{6}
=2
$