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2(5x+1)-5-2x=2-2(3x+1)
We move all terms to the left:
2(5x+1)-5-2x-(2-2(3x+1))=0
We add all the numbers together, and all the variables
-2x+2(5x+1)-(2-2(3x+1))-5=0
We multiply parentheses
-2x+10x-(2-2(3x+1))+2-5=0
We calculate terms in parentheses: -(2-2(3x+1)), so:We add all the numbers together, and all the variables
2-2(3x+1)
determiningTheFunctionDomain -2(3x+1)+2
We multiply parentheses
-6x-2+2
We add all the numbers together, and all the variables
-6x
Back to the equation:
-(-6x)
8x-(-6x)-3=0
We get rid of parentheses
8x+6x-3=0
We add all the numbers together, and all the variables
14x-3=0
We move all terms containing x to the left, all other terms to the right
14x=3
x=3/14
x=3/14
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