1/(x+1)-1/(x+2)=2

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Solution for 1/(x+1)-1/(x+2)=2 equation: 



1/(x+1)-1/(x+2)=2

We move all terms to the left:

1/(x+1)-1/(x+2)-(2)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We calculate fractions


(1*(x+2))/((x+1)*(x+2))+(-1*(x+1))/((x+1)*(x+2))-2=0



We calculate terms in parentheses: +(1*(x+2))/((x+1)*(x+2)), so:

1*(x+2))/((x+1)*(x+2)

We multiply all the terms by the denominator


1*(x+2))

Back to the equation:

+(1*(x+2)))





We calculate terms in parentheses: +(-1*(x+1))/((x+1)*(x+2)), so:

-1*(x+1))/((x+1)*(x+2)

We multiply all the terms by the denominator


-1*(x+1))

Back to the equation:

+(-1*(x+1)))

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