2(5i-2)=3(2i+3)-1

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Solution for 2(5i-2)=3(2i+3)-1 equation: 



2(5i-2)=3(2i+3)-1

We move all terms to the left:

2(5i-2)-(3(2i+3)-1)=0

We multiply parentheses

10i-(3(2i+3)-1)-4=0



We calculate terms in parentheses: -(3(2i+3)-1), so:

3(2i+3)-1

We multiply parentheses

6i+9-1

We add all the numbers together, and all the variables

6i+8

Back to the equation:

-(6i+8)



We get rid of parentheses

10i-6i-8-4=0

We add all the numbers together, and all the variables

4i-12=0

We move all terms containing i to the left, all other terms to the right

4i=12

i=12/4

i=3

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