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3x+2(4x+1)=5x-3(2x-4)
We move all terms to the left:
3x+2(4x+1)-(5x-3(2x-4))=0
We multiply parentheses
3x+8x-(5x-3(2x-4))+2=0
We calculate terms in parentheses: -(5x-3(2x-4)), so:We add all the numbers together, and all the variables
5x-3(2x-4)
We multiply parentheses
5x-6x+12
We add all the numbers together, and all the variables
-1x+12
Back to the equation:
-(-1x+12)
11x-(-1x+12)+2=0
We get rid of parentheses
11x+1x-12+2=0
We add all the numbers together, and all the variables
12x-10=0
We move all terms containing x to the left, all other terms to the right
12x=10
x=10/12
x=5/6
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