2(5c-2)-2c=(2c+3)+7

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Solution for 2(5c-2)-2c=(2c+3)+7 equation: 



2(5c-2)-2c=(2c+3)+7

We move all terms to the left:

2(5c-2)-2c-((2c+3)+7)=0

We add all the numbers together, and all the variables

-2c+2(5c-2)-((2c+3)+7)=0

We multiply parentheses

-2c+10c-((2c+3)+7)-4=0



We calculate terms in parentheses: -((2c+3)+7), so:

(2c+3)+7

We get rid of parentheses

2c+3+7

We add all the numbers together, and all the variables

2c+10

Back to the equation:

-(2c+10)



We add all the numbers together, and all the variables

8c-(2c+10)-4=0

We get rid of parentheses

8c-2c-10-4=0

We add all the numbers together, and all the variables

6c-14=0

We move all terms containing c to the left, all other terms to the right

6c=14

c=14/6

c=2+1/3

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