(c-1)+2(3c+1)=-(3c+1)

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Solution for (c-1)+2(3c+1)=-(3c+1) equation: 



(c-1)+2(3c+1)=-(3c+1)

We move all terms to the left:

(c-1)+2(3c+1)-(-(3c+1))=0

We multiply parentheses

(c-1)+6c-(-(3c+1))+2=0

We get rid of parentheses

c+6c-(-(3c+1))-1+2=0



We calculate terms in parentheses: -(-(3c+1)), so:

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)



We add all the numbers together, and all the variables

7c-(-3c-1)+1=0

We get rid of parentheses

7c+3c+1+1=0

We add all the numbers together, and all the variables

10c+2=0

We move all terms containing c to the left, all other terms to the right

10c=-2

c=-2/10

c=-1/5

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