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2(5c+3)=8+2(c+3)
We move all terms to the left:
2(5c+3)-(8+2(c+3))=0
We multiply parentheses
10c-(8+2(c+3))+6=0
We calculate terms in parentheses: -(8+2(c+3)), so:We get rid of parentheses
8+2(c+3)
determiningTheFunctionDomain 2(c+3)+8
We multiply parentheses
2c+6+8
We add all the numbers together, and all the variables
2c+14
Back to the equation:
-(2c+14)
10c-2c-14+6=0
We add all the numbers together, and all the variables
8c-8=0
We move all terms containing c to the left, all other terms to the right
8c=8
c=8/8
c=1
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