2(5b-7)=2(b-35)

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Solution for 2(5b-7)=2(b-35) equation: 



2(5b-7)=2(b-35)

We move all terms to the left:

2(5b-7)-(2(b-35))=0

We multiply parentheses

10b-(2(b-35))-14=0



We calculate terms in parentheses: -(2(b-35)), so:

2(b-35)

We multiply parentheses

2b-70

Back to the equation:

-(2b-70)



We get rid of parentheses

10b-2b+70-14=0

We add all the numbers together, and all the variables

8b+56=0

We move all terms containing b to the left, all other terms to the right

8b=-56

b=-56/8

b=-7

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