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2(5a-1)=3(a+11)
We move all terms to the left:
2(5a-1)-(3(a+11))=0
We multiply parentheses
10a-(3(a+11))-2=0
We calculate terms in parentheses: -(3(a+11)), so:We get rid of parentheses
3(a+11)
We multiply parentheses
3a+33
Back to the equation:
-(3a+33)
10a-3a-33-2=0
We add all the numbers together, and all the variables
7a-35=0
We move all terms containing a to the left, all other terms to the right
7a=35
a=35/7
a=5
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