2(4y+1)=3(7y-2)

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Solution for 2(4y+1)=3(7y-2) equation: 



2(4y+1)=3(7y-2)

We move all terms to the left:

2(4y+1)-(3(7y-2))=0

We multiply parentheses

8y-(3(7y-2))+2=0



We calculate terms in parentheses: -(3(7y-2)), so:

3(7y-2)

We multiply parentheses

21y-6

Back to the equation:

-(21y-6)



We get rid of parentheses

8y-21y+6+2=0

We add all the numbers together, and all the variables

-13y+8=0

We move all terms containing y to the left, all other terms to the right

-13y=-8

y=-8/-13

y=8/13

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