1/8(a+4)=1/5(9-a)

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Solution for 1/8(a+4)=1/5(9-a) equation: 



1/8(a+4)=1/5(9-a)

We move all terms to the left:

1/8(a+4)-(1/5(9-a))=0



Domain of the equation: 8(a+4)!=0

a∈R





Domain of the equation: 5(9-a))!=0

a∈R



We add all the numbers together, and all the variables

1/8(a+4)-(1/5(-1a+9))=0

We calculate fractions


(5a(-)/(8(a+4)*5(-1a+9)))+(-8aa/(8(a+4)*5(-1a+9)))=0



We calculate terms in parentheses: +(5a(-)/(8(a+4)*5(-1a+9))), so:

5a(-)/(8(a+4)*5(-1a+9))

We add all the numbers together, and all the variables

5a0/(8(a+4)*5(-1a+9))

We multiply all the terms by the denominator


5a0

We add all the numbers together, and all the variables

5a

Back to the equation:

+(5a)





We calculate terms in parentheses: +(-8aa/(8(a+4)*5(-1a+9))), so:

-8aa/(8(a+4)*5(-1a+9))

We multiply all the terms by the denominator


-8aa

Back to the equation:

+(-8aa)



We get rid of parentheses

5a-8aa=0

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