2(4x-8)=-42+10

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Solution for 2(4x-8)=-42+10 equation: 



2(4x-8)=-42+10

We move all terms to the left:

2(4x-8)-(-42+10)=0

We add all the numbers together, and all the variables

2(4x-8)-(-32)=0

We add all the numbers together, and all the variables

2(4x-8)+32=0

We multiply parentheses

8x-16+32=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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