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2(x-2)+8=6x-4(-1+x)
We move all terms to the left:
2(x-2)+8-(6x-4(-1+x))=0
We add all the numbers together, and all the variables
2(x-2)-(6x-4(x-1))+8=0
We multiply parentheses
2x-(6x-4(x-1))-4+8=0
We calculate terms in parentheses: -(6x-4(x-1)), so:We add all the numbers together, and all the variables
6x-4(x-1)
We multiply parentheses
6x-4x+4
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
2x-(2x+4)+4=0
We get rid of parentheses
2x-2x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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