2(4x-1)+3(x+4)=6x+29

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Solution for 2(4x-1)+3(x+4)=6x+29 equation: 



2(4x-1)+3(x+4)=6x+29

We move all terms to the left:

2(4x-1)+3(x+4)-(6x+29)=0

We multiply parentheses

8x+3x-(6x+29)-2+12=0

We get rid of parentheses

8x+3x-6x-29-2+12=0

We add all the numbers together, and all the variables

5x-19=0

We move all terms containing x to the left, all other terms to the right

5x=19

x=19/5

x=3+4/5

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