3(x-1)+7=4x+-3(2-x)

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Solution for 3(x-1)+7=4x+-3(2-x) equation: 



3(x-1)+7=4x+-3(2-x)

We move all terms to the left:

3(x-1)+7-(4x+-3(2-x))=0

We add all the numbers together, and all the variables

3(x-1)-(4x+-3(-1x+2))+7=0

We use the square of the difference formula

3(x-1)-(4x-3(-1x+2))+7=0

We multiply parentheses

3x-(4x-3(-1x+2))-3+7=0



We calculate terms in parentheses: -(4x-3(-1x+2)), so:

4x-3(-1x+2)

We multiply parentheses

4x+3x-6

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

3x-(7x-6)+4=0

We get rid of parentheses

3x-7x+6+4=0

We add all the numbers together, and all the variables

-4x+10=0

We move all terms containing x to the left, all other terms to the right

-4x=-10

x=-10/-4

x=2+1/2

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