2(4x+3)+7x=16x-1

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Solution for 2(4x+3)+7x=16x-1 equation: 



2(4x+3)+7x=16x-1

We move all terms to the left:

2(4x+3)+7x-(16x-1)=0

We add all the numbers together, and all the variables

7x+2(4x+3)-(16x-1)=0

We multiply parentheses

7x+8x-(16x-1)+6=0

We get rid of parentheses

7x+8x-16x+1+6=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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