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6(X+2)+4(X-3)=59
We move all terms to the left:
6(X+2)+4(X-3)-(59)=0
We multiply parentheses
6X+4X+12-12-59=0
We add all the numbers together, and all the variables
10X-59=0
We move all terms containing X to the left, all other terms to the right
10X=59
X=59/10
X=5+9/10
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