2(4x+2)=4x-12(1x-1)

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Solution for 2(4x+2)=4x-12(1x-1) equation: 



2(4x+2)=4x-12(1x-1)

We move all terms to the left:

2(4x+2)-(4x-12(1x-1))=0

We add all the numbers together, and all the variables

2(4x+2)-(4x-12(x-1))=0

We multiply parentheses

8x-(4x-12(x-1))+4=0



We calculate terms in parentheses: -(4x-12(x-1)), so:

4x-12(x-1)

We multiply parentheses

4x-12x+12

We add all the numbers together, and all the variables

-8x+12

Back to the equation:

-(-8x+12)



We get rid of parentheses

8x+8x-12+4=0

We add all the numbers together, and all the variables

16x-8=0

We move all terms containing x to the left, all other terms to the right

16x=8

x=8/16

x=1/2

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