2(4x+2)=4x+12(x-1)

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Solution for 2(4x+2)=4x+12(x-1) equation:



2(4x+2)=4x+12(x-1)
We move all terms to the left:
2(4x+2)-(4x+12(x-1))=0
We multiply parentheses
8x-(4x+12(x-1))+4=0
We calculate terms in parentheses: -(4x+12(x-1)), so:
4x+12(x-1)
We multiply parentheses
4x+12x-12
We add all the numbers together, and all the variables
16x-12
Back to the equation:
-(16x-12)
We get rid of parentheses
8x-16x+12+4=0
We add all the numbers together, and all the variables
-8x+16=0
We move all terms containing x to the left, all other terms to the right
-8x=-16
x=-16/-8
x=+2

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