3y2+51=918

Solution for 3y2+51=918 equation:

3y^2+51=918

We move all terms to the left:

3y^2+51-(918)=0

We add all the numbers together, and all the variables

3y^2-867=0

a = 3; b = 0; c = -867;
Δ = b2-4ac
Δ = 02-4·3·(-867)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-102}{2*3}=\frac{-102}{6}
=-17
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+102}{2*3}=\frac{102}{6}
=17
$