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2(4x+2)*2(6x)=84
We move all terms to the left:
2(4x+2)*2(6x)-(84)=0
We multiply parentheses
208x^2+104x-84=0
a = 208; b = 104; c = -84;
Δ = b2-4ac
Δ = 1042-4·208·(-84)
Δ = 80704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80704}=\sqrt{64*1261}=\sqrt{64}*\sqrt{1261}=8\sqrt{1261}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-8\sqrt{1261}}{2*208}=\frac{-104-8\sqrt{1261}}{416} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+8\sqrt{1261}}{2*208}=\frac{-104+8\sqrt{1261}}{416} $
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