6(1y-1)=32

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Solution for 6(1y-1)=32 equation: 



6(1y-1)=32

We move all terms to the left:

6(1y-1)-(32)=0

We add all the numbers together, and all the variables

6(y-1)-32=0

We multiply parentheses

6y-6-32=0

We add all the numbers together, and all the variables

6y-38=0

We move all terms containing y to the left, all other terms to the right

6y=38

y=38/6

y=6+1/3

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