2(4x+1.5)=4x+11+2x+32

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Solution for 2(4x+1.5)=4x+11+2x+32 equation:



2(4x+1.5)=4x+11+2x+32
We move all terms to the left:
2(4x+1.5)-(4x+11+2x+32)=0
We add all the numbers together, and all the variables
2(4x+1.5)-(6x+43)=0
We multiply parentheses
8x-(6x+43)+3=0
We get rid of parentheses
8x-6x-43+3=0
We add all the numbers together, and all the variables
2x-40=0
We move all terms containing x to the left, all other terms to the right
2x=40
x=40/2
x=20

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