2(d-4)=5(4-d)

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Solution for 2(d-4)=5(4-d) equation:



2(d-4)=5(4-d)
We move all terms to the left:
2(d-4)-(5(4-d))=0
We add all the numbers together, and all the variables
2(d-4)-(5(-1d+4))=0
We multiply parentheses
2d-(5(-1d+4))-8=0
We calculate terms in parentheses: -(5(-1d+4)), so:
5(-1d+4)
We multiply parentheses
-5d+20
Back to the equation:
-(-5d+20)
We get rid of parentheses
2d+5d-20-8=0
We add all the numbers together, and all the variables
7d-28=0
We move all terms containing d to the left, all other terms to the right
7d=28
d=28/7
d=4

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