2(4x+1)=32

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Solution for 2(4x+1)=32 equation: 



2(4x+1)=32

We move all terms to the left:

2(4x+1)-(32)=0

We multiply parentheses

8x+2-32=0

We add all the numbers together, and all the variables

8x-30=0

We move all terms containing x to the left, all other terms to the right

8x=30

x=30/8

x=3+3/4

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