-3(y+1)=7y-5+2(3y+8)

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Solution for -3(y+1)=7y-5+2(3y+8) equation: 



-3(y+1)=7y-5+2(3y+8)

We move all terms to the left:

-3(y+1)-(7y-5+2(3y+8))=0

We multiply parentheses

-3y-(7y-5+2(3y+8))-3=0



We calculate terms in parentheses: -(7y-5+2(3y+8)), so:

7y-5+2(3y+8)

determiningTheFunctionDomain
7y+2(3y+8)-5

We multiply parentheses

7y+6y+16-5

We add all the numbers together, and all the variables

13y+11

Back to the equation:

-(13y+11)



We get rid of parentheses

-3y-13y-11-3=0

We add all the numbers together, and all the variables

-16y-14=0

We move all terms containing y to the left, all other terms to the right

-16y=14

y=14/-16

y=-7/8

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