2(4v+1)=13

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Solution for 2(4v+1)=13 equation: 



2(4v+1)=13

We move all terms to the left:

2(4v+1)-(13)=0

We multiply parentheses

8v+2-13=0

We add all the numbers together, and all the variables

8v-11=0

We move all terms containing v to the left, all other terms to the right

8v=11

v=11/8

v=1+3/8

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