3y+2(5y-3)=7

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Solution for 3y+2(5y-3)=7 equation: 



3y+2(5y-3)=7

We move all terms to the left:

3y+2(5y-3)-(7)=0

We multiply parentheses

3y+10y-6-7=0

We add all the numbers together, and all the variables

13y-13=0

We move all terms containing y to the left, all other terms to the right

13y=13

y=13/13

y=1

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