2(4p-5)-(p-4)=3(p+2)+4(p-3)

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Solution for 2(4p-5)-(p-4)=3(p+2)+4(p-3) equation: 



2(4p-5)-(p-4)=3(p+2)+4(p-3)

We move all terms to the left:

2(4p-5)-(p-4)-(3(p+2)+4(p-3))=0

We multiply parentheses

8p-(p-4)-(3(p+2)+4(p-3))-10=0

We get rid of parentheses

8p-p-(3(p+2)+4(p-3))+4-10=0



We calculate terms in parentheses: -(3(p+2)+4(p-3)), so:

3(p+2)+4(p-3)

We multiply parentheses

3p+4p+6-12

We add all the numbers together, and all the variables

7p-6

Back to the equation:

-(7p-6)



We add all the numbers together, and all the variables

7p-(7p-6)-6=0

We get rid of parentheses

7p-7p+6-6=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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