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X=9/2X-5
We move all terms to the left:
X-(9/2X-5)=0
Domain of the equation: 2X-5)!=0We get rid of parentheses
X∈R
X-9/2X+5=0
We multiply all the terms by the denominator
X*2X+5*2X-9=0
Wy multiply elements
2X^2+10X-9=0
a = 2; b = 10; c = -9;
Δ = b2-4ac
Δ = 102-4·2·(-9)
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{43}}{2*2}=\frac{-10-2\sqrt{43}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{43}}{2*2}=\frac{-10+2\sqrt{43}}{4} $
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