2(4m-3)=7m+21

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Solution for 2(4m-3)=7m+21 equation: 



2(4m-3)=7m+21

We move all terms to the left:

2(4m-3)-(7m+21)=0

We multiply parentheses

8m-(7m+21)-6=0

We get rid of parentheses

8m-7m-21-6=0

We add all the numbers together, and all the variables

m-27=0

We move all terms containing m to the left, all other terms to the right

m=27

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