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5(x-7)=2(2x-10)
We move all terms to the left:
5(x-7)-(2(2x-10))=0
We multiply parentheses
5x-(2(2x-10))-35=0
We calculate terms in parentheses: -(2(2x-10)), so:We get rid of parentheses
2(2x-10)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
5x-4x+20-35=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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