2(4m+5)+8(3m+1)=32m+18

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Solution for 2(4m+5)+8(3m+1)=32m+18 equation: 



2(4m+5)+8(3m+1)=32m+18

We move all terms to the left:

2(4m+5)+8(3m+1)-(32m+18)=0

We multiply parentheses

8m+24m-(32m+18)+10+8=0

We get rid of parentheses

8m+24m-32m-18+10+8=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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