x+18=4+(2x+22)

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Solution for x+18=4+(2x+22) equation:



x+18=4+(2x+22)
We move all terms to the left:
x+18-(4+(2x+22))=0
We calculate terms in parentheses: -(4+(2x+22)), so:
4+(2x+22)
determiningTheFunctionDomain (2x+22)+4
We get rid of parentheses
2x+22+4
We add all the numbers together, and all the variables
2x+26
Back to the equation:
-(2x+26)
We get rid of parentheses
x-2x-26+18=0
We add all the numbers together, and all the variables
-1x-8=0
We move all terms containing x to the left, all other terms to the right
-x=8
x=8/-1
x=-8

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