2(4l-2)+1=4(l+1)-3

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Solution for 2(4l-2)+1=4(l+1)-3 equation: 



2(4l-2)+1=4(l+1)-3

We move all terms to the left:

2(4l-2)+1-(4(l+1)-3)=0

We multiply parentheses

8l-(4(l+1)-3)-4+1=0



We calculate terms in parentheses: -(4(l+1)-3), so:

4(l+1)-3

We multiply parentheses

4l+4-3

We add all the numbers together, and all the variables

4l+1

Back to the equation:

-(4l+1)



We add all the numbers together, and all the variables

8l-(4l+1)-3=0

We get rid of parentheses

8l-4l-1-3=0

We add all the numbers together, and all the variables

4l-4=0

We move all terms containing l to the left, all other terms to the right

4l=4

l=4/4

l=1

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