3x+2(x+3)=4(x+1)-1

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Solution for 3x+2(x+3)=4(x+1)-1 equation: 



3x+2(x+3)=4(x+1)-1

We move all terms to the left:

3x+2(x+3)-(4(x+1)-1)=0

We multiply parentheses

3x+2x-(4(x+1)-1)+6=0



We calculate terms in parentheses: -(4(x+1)-1), so:

4(x+1)-1

We multiply parentheses

4x+4-1

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We add all the numbers together, and all the variables

5x-(4x+3)+6=0

We get rid of parentheses

5x-4x-3+6=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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