2(4i+3)+3(2i-1)=31

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Solution for 2(4i+3)+3(2i-1)=31 equation: 



2(4i+3)+3(2i-1)=31

We move all terms to the left:

2(4i+3)+3(2i-1)-(31)=0

We multiply parentheses

8i+6i+6-3-31=0

We add all the numbers together, and all the variables

14i-28=0

We move all terms containing i to the left, all other terms to the right

14i=28

i=28/14

i=2

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