2(4c+2)=4c-12(c-1)

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Solution for 2(4c+2)=4c-12(c-1) equation: 



2(4c+2)=4c-12(c-1)

We move all terms to the left:

2(4c+2)-(4c-12(c-1))=0

We multiply parentheses

8c-(4c-12(c-1))+4=0



We calculate terms in parentheses: -(4c-12(c-1)), so:

4c-12(c-1)

We multiply parentheses

4c-12c+12

We add all the numbers together, and all the variables

-8c+12

Back to the equation:

-(-8c+12)



We get rid of parentheses

8c+8c-12+4=0

We add all the numbers together, and all the variables

16c-8=0

We move all terms containing c to the left, all other terms to the right

16c=8

c=8/16

c=1/2

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