5(y-1)=-2(2y-3)

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Solution for 5(y-1)=-2(2y-3) equation: 



5(y-1)=-2(2y-3)

We move all terms to the left:

5(y-1)-(-2(2y-3))=0

We multiply parentheses

5y-(-2(2y-3))-5=0



We calculate terms in parentheses: -(-2(2y-3)), so:

-2(2y-3)

We multiply parentheses

-4y+6

Back to the equation:

-(-4y+6)



We get rid of parentheses

5y+4y-6-5=0

We add all the numbers together, and all the variables

9y-11=0

We move all terms containing y to the left, all other terms to the right

9y=11

y=11/9

y=1+2/9

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