2(4a-5)+7a=-38+8a

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Solution for 2(4a-5)+7a=-38+8a equation:



2(4a-5)+7a=-38+8a
We move all terms to the left:
2(4a-5)+7a-(-38+8a)=0
We add all the numbers together, and all the variables
2(4a-5)+7a-(8a-38)=0
We add all the numbers together, and all the variables
7a+2(4a-5)-(8a-38)=0
We multiply parentheses
7a+8a-(8a-38)-10=0
We get rid of parentheses
7a+8a-8a+38-10=0
We add all the numbers together, and all the variables
7a+28=0
We move all terms containing a to the left, all other terms to the right
7a=-28
a=-28/7
a=-4

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