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-1/4x=-20x
We move all terms to the left:
-1/4x-(-20x)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
-1/4x+20x=0
We multiply all the terms by the denominator
20x*4x-1=0
Wy multiply elements
80x^2-1=0
a = 80; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·80·(-1)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*80}=\frac{0-8\sqrt{5}}{160} =-\frac{8\sqrt{5}}{160} =-\frac{\sqrt{5}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*80}=\frac{0+8\sqrt{5}}{160} =\frac{8\sqrt{5}}{160} =\frac{\sqrt{5}}{20} $
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