2(4Z-11)=3(3z+11)-z

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Solution for 2(4Z-11)=3(3z+11)-z equation: 



2(4-11)=3(3Z+11)-Z

We move all terms to the left:

2(4-11)-(3(3Z+11)-Z)=0

We add all the numbers together, and all the variables

-(3(3Z+11)-Z)+2(-7)=0

We add all the numbers together, and all the variables

-(3(3Z+11)-Z)-14=0



We calculate terms in parentheses: -(3(3Z+11)-Z), so:

3(3Z+11)-Z

We add all the numbers together, and all the variables

-1Z+3(3Z+11)

We multiply parentheses

-1Z+9Z+33

We add all the numbers together, and all the variables

8Z+33

Back to the equation:

-(8Z+33)



We get rid of parentheses

-8Z-33-14=0

We add all the numbers together, and all the variables

-8Z-47=0

We move all terms containing Z to the left, all other terms to the right

-8Z=47

Z=47/-8

Z=-5+7/8

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