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-2(z-8)=1/4(12z+4)
We move all terms to the left:
-2(z-8)-(1/4(12z+4))=0
Domain of the equation: 4(12z+4))!=0We multiply parentheses
z∈R
-2z-(1/4(12z+4))+16=0
We multiply all the terms by the denominator
-2z*4(12z+4))-(1+16*4(12z+4))=0
Wy multiply elements
-8z^2(1+64z(1=0
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