2(4K-3)=4(2k-3)+6

Solution for 2(4K-3)=4(2k-3)+6 equation:

2(4-3)=4(2K-3)+6

We move all terms to the left:

2(4-3)-(4(2K-3)+6)=0

We add all the numbers together, and all the variables

-(4(2K-3)+6)+21=0


We calculate terms in parentheses: -(4(2K-3)+6), so:

4(2K-3)+6

We multiply parentheses

8K-12+6

We add all the numbers together, and all the variables

8K-6

Back to the equation:

-(8K-6)


We get rid of parentheses

-8K+6+21=0

We add all the numbers together, and all the variables

-8K+27=0

We move all terms containing K to the left, all other terms to the right

-8K=-27

K=-27/-8

K=3+3/8