3k-10=-1+3(2k-1)

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Solution for 3k-10=-1+3(2k-1) equation: 



3k-10=-1+3(2k-1)

We move all terms to the left:

3k-10-(-1+3(2k-1))=0



We calculate terms in parentheses: -(-1+3(2k-1)), so:

-1+3(2k-1)

determiningTheFunctionDomain
3(2k-1)-1

We multiply parentheses

6k-3-1

We add all the numbers together, and all the variables

6k-4

Back to the equation:

-(6k-4)



We get rid of parentheses

3k-6k+4-10=0

We add all the numbers together, and all the variables

-3k-6=0

We move all terms containing k to the left, all other terms to the right

-3k=6

k=6/-3

k=-2

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