2(4-a)=3(a+1)-5(a-1)

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Solution for 2(4-a)=3(a+1)-5(a-1) equation:


Simplifying
2(4 + -1a) = 3(a + 1) + -5(a + -1)
(4 * 2 + -1a * 2) = 3(a + 1) + -5(a + -1)
(8 + -2a) = 3(a + 1) + -5(a + -1)

Reorder the terms:
8 + -2a = 3(1 + a) + -5(a + -1)
8 + -2a = (1 * 3 + a * 3) + -5(a + -1)
8 + -2a = (3 + 3a) + -5(a + -1)

Reorder the terms:
8 + -2a = 3 + 3a + -5(-1 + a)
8 + -2a = 3 + 3a + (-1 * -5 + a * -5)
8 + -2a = 3 + 3a + (5 + -5a)

Reorder the terms:
8 + -2a = 3 + 5 + 3a + -5a

Combine like terms: 3 + 5 = 8
8 + -2a = 8 + 3a + -5a

Combine like terms: 3a + -5a = -2a
8 + -2a = 8 + -2a

Add '-8' to each side of the equation.
8 + -8 + -2a = 8 + -8 + -2a

Combine like terms: 8 + -8 = 0
0 + -2a = 8 + -8 + -2a
-2a = 8 + -8 + -2a

Combine like terms: 8 + -8 = 0
-2a = 0 + -2a
-2a = -2a

Add '2a' to each side of the equation.
-2a + 2a = -2a + 2a

Combine like terms: -2a + 2a = 0
0 = -2a + 2a

Combine like terms: -2a + 2a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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