2(b-3)+3(b+4)=b+14

Solution for 2(b-3)+3(b+4)=b+14 equation:

Simplifying
2(b + -3) + 3(b + 4) = b + 14

Reorder the terms:
2(-3 + b) + 3(b + 4) = b + 14
(-3 * 2 + b * 2) + 3(b + 4) = b + 14
(-6 + 2b) + 3(b + 4) = b + 14

Reorder the terms:
-6 + 2b + 3(4 + b) = b + 14
-6 + 2b + (4 * 3 + b * 3) = b + 14
-6 + 2b + (12 + 3b) = b + 14

Reorder the terms:
-6 + 12 + 2b + 3b = b + 14

Combine like terms: -6 + 12 = 6
6 + 2b + 3b = b + 14

Combine like terms: 2b + 3b = 5b
6 + 5b = b + 14

Reorder the terms:
6 + 5b = 14 + b

Solving
6 + 5b = 14 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
6 + 5b + -1b = 14 + b + -1b

Combine like terms: 5b + -1b = 4b
6 + 4b = 14 + b + -1b

Combine like terms: b + -1b = 0
6 + 4b = 14 + 0
6 + 4b = 14

Add '-6' to each side of the equation.
6 + -6 + 4b = 14 + -6

Combine like terms: 6 + -6 = 0
0 + 4b = 14 + -6
4b = 14 + -6

Combine like terms: 14 + -6 = 8
4b = 8

Divide each side by '4'.
b = 2

Simplifying
b = 2