2(4-2r)=2(r-5)

Solution for 2(4-2r)=2(r-5) equation:

2(4-2r)=2(r-5)

We move all terms to the left:

2(4-2r)-(2(r-5))=0

We add all the numbers together, and all the variables

2(-2r+4)-(2(r-5))=0

We multiply parentheses

-4r-(2(r-5))+8=0


We calculate terms in parentheses: -(2(r-5)), so:

2(r-5)

We multiply parentheses

2r-10

Back to the equation:

-(2r-10)


We get rid of parentheses

-4r-2r+10+8=0

We add all the numbers together, and all the variables

-6r+18=0

We move all terms containing r to the left, all other terms to the right

-6r=-18

r=-18/-6

r=+3