2u-1=4(2-u)-3

Solution for 2u-1=4(2-u)-3 equation:

2u-1=4(2-u)-3

We move all terms to the left:

2u-1-(4(2-u)-3)=0

We add all the numbers together, and all the variables

2u-(4(-1u+2)-3)-1=0


We calculate terms in parentheses: -(4(-1u+2)-3), so:

4(-1u+2)-3

We multiply parentheses

-4u+8-3

We add all the numbers together, and all the variables

-4u+5

Back to the equation:

-(-4u+5)


We get rid of parentheses

2u+4u-5-1=0

We add all the numbers together, and all the variables

6u-6=0

We move all terms containing u to the left, all other terms to the right

6u=6

u=6/6

u=1